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Steph makes 90\%90%90, percent of the free throws she attempts. She is going to shoot 333 free throws. Assume that the results of free throws are independent from each other. Let XXX represent the number of free throws she makes.
Find the probability that Steph makes exactly 111 of the 333 free throws.

Answer :

Answer:

0.972

Step-by-step explanation:

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Using the concept of binomial probability, the probability of making exactly 11 throws is [tex]6.073 \times 10^{-15} [/tex]

Recall :

  • P(x = x) = nCx * p^x * q^(n-x)
  • p = probability of success = 0.9
  • n = number of trials = 33
  • q = 1 - p = 0.1

The probability of making exactly 11 throws can be defined thus :

  • P(X = 11) = 33C11 * 0.9^11 * 0.1^22

Using a binomial probability calculator :

P(X = 11) = [tex]6.073 \times 10^{-15} [/tex]

Therefore, the probability is [tex]6.073 \times 10^{-15} [/tex]

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