Answer:
The fourth term of given geometric sequence is 5/9
Step-by-step explanation:
The general formula for geometric sequence is given by:
[tex]a_n = a_1.r^{(n-1)}[/tex]
Here a_n is the nth term,
a_1 is the first term
and r is the common ratio.
It is given in the question that
[tex]a_1 = 15\\r = \frac{1}{3}[/tex]
Putting these values
[tex]a_n = 15 . (\frac{1}{3})^{n-1}[/tex]
For 4th term, we will put n=4
So,
[tex]a_4 = 15 . (\frac{1}{3})^{4-1}\\a_4 = 15 . (\frac{1}{3})^3\\a_4 = 15 . \frac{1}{27}\\a_4 = \frac{15}{27}\\a_4 = \frac{5}{9}[/tex]
Hence,
The fourth term of given geometric sequence is 5/9
