Answer:
(–3, –2)
Step-by-step explanation:
A linear equation is an equation in the form y = mx + b, where m is the slope of the line and b is the y intercept.
Equation A is represented by the points:
x: -5 -2 0 1
y: -4 -1 1 2
Equation A can be gotten by picking any two pair of points. Let us use (-5, -4) and (0, 1). We use this formula:
[tex]y- y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-(-4)=\frac{1-(-4)}{0-(-5)} (x-(-5))\\\\y +4=x+5\\\\y=x+1[/tex]
Equation B is represented by the points:
x: -6 -3 3 6
y: -4 -2 2 4
Equation B can be gotten by picking any two pair of points. Let us use (-6, -4) and (3, 2). We use this formula:
[tex]y- y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-(-4)=\frac{2-(-4)}{3-(-5)} (x-(-6))\\\\y +4=\frac{2}{3}( x+6)\\\\y+4=\frac{2}{3} x+4\\\\y=\frac{2}{3}x[/tex]
The solution to the system of equations is gotten by solving y = x + 1 and y = (2/3)x simultaneously.
Substitute y = (2/3)x in y = x + 1:
(2/3)x = x + 1
2x = 3x + 3
x = -3
Put x = -3 in y = (2/3)x
y = (2/3) (-3) = -2
Hence (-3, -2) is the solution
