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A 33 kg child on a swing has a potential energy of 720 J with respect to the ground. What is the child’s height above the ground? please answer soon

Answer :

Alejanndraaxgo

Answer:

h = 2.22 m

Explanation:

Using the international system, we know that the gravity of the earth is 9.8 m / s².

then, we have as data:

  • Potential Energy (Ep) = 720 J
  • Mass (m) = 33 kg
  • Gravity (g) = 9.8 m/s²
  • Height (h) = ?

Use formula:

  • [tex]\boxed{h=\frac{Ep}{m*g}}[/tex]

Replace:

  • [tex]\boxed{h=\frac{720J}{33kg*9.8\frac{m}{s^{2}}}}[/tex]

Joules descompose:

  • [tex]\boxed{h=\frac{720N*m}{33kg*9.8\frac{m}{s^{2}}}}[/tex]

Solve the multiply of mass and gravity:

  • [tex]\boxed{h=\frac{720N*m}{323.4kg*\frac{m}{s^{2}}}}[/tex]

Multiply the units. Knowing that kg * m/s² = N, so:

  • [tex]\boxed{h=\frac{720N*m}{323.4N}}}[/tex]

Simplify the Newtons (N), and it divides:

  • [tex]\boxed{h=2.22\ m}[/tex]

What is the child’s height above the ground?

The child's height above the ground is 2.22 meters.

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