Answer:
260 in²
Step-by-step explanation:
1) Find the total area of the triangular sides
[tex]A=\frac{1}{2}bh[/tex]
Plug in 10 in as the base and 8 in as the height
[tex]A=\frac{1}{2}(10)(8)\\A=\frac{1}{2}(80)\\A=40[/tex]
Multiply the area by 4 (for the 4 triangular surfaces)
[tex]40*4\\=160[/tex]
Therefore the total area of the triangular sides is 160 in².
2) Find the area of the square base
[tex]A=l^2[/tex]
Plug in 10 as the length
[tex]A=10^2\\A=100[/tex]
Therefore, the area of the square base is 100 in².
3) Add the areas together
100 in² + 160 in²
= 260 in²
Therefore, the surface area of the solid is 260 in².
I hope this helps!
