Answer:
[tex]Phase\ Shift = -\frac{c}{b}[/tex]
Step-by-step explanation:
See comment for complete question
Given
[tex]f(x) = Asin(bx+c)+d[/tex]
Required
Determine an expression for the phase shift
[tex]f(x) = Asin(bx+c)+d[/tex]
Factorize the expression in bracket
[tex]f(x) = Asin(b(x+\frac{c}{b}))+d[/tex]
The general expression is:
[tex]F(t) = A f(B(t - C/B)) + D[/tex]
Where:
C/B is the phase shift
By comparing the general expression with: [tex]f(x) = Asin(b(x+\frac{c}{b}))+d[/tex]
[tex]-\frac{C}{B} = \frac{c}{b}[/tex]
Multiply both sides by -1
[tex]\frac{C}{B} = -\frac{c}{b}[/tex]
Hence:
[tex]Phase\ Shift = -\frac{c}{b}[/tex]
