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In a pile of coins, there are 7 more quarters than nickels. If there is a
total of $2.65 in coins, how many total coins are there? How many
of each type of coin is in the pile? Guess, check, and revise to solve

Answer :

Answer:

Step-by-step explanation:

Let x = to the number of nickels.

Let x + 7 = the number of quarters.

So multiply x by .05 to find out how much the nickles are worth and

multiply x + 7 by .25  to find out how much the quarters are worth.

Then add them together to get the total and solve.

.05x + .25(x + 7) = 2.65

.05x + .25x + 1.75 = 2.65

.30x + 1.75 = 2.65

Subtract 1.75 from each side of the equation.

.30x = .90

x = 3

x + 7 = 10

So 10 is the number of quarters.

Answer:

Step-by-step explanation:

we only have to have 7 more quarters than nickels.. so put one nickel and 8 quarters

that's $2.05

now make up the rest to make 2.65

add 6 dimes and you've got it :)

1 nickel

6 dimes

8 quarters

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