Hi there!
[tex]\large\boxed{(4y + 1)(2y + 1)}[/tex]
8y² + 6y + 1
Factored form is as such:
(ax + b)(cx + d), where:
a · c = 8
bc + da = 6
b · d = 1
After guessing and checking, we get:
(4y + 1)(2y + 1)
Step-by-step explanation:
By splitting middle term method:
= 8y² + 2y + 4y + 1
= 2y(4y + 1) + 1(4y + 1)
= (2y + 1) (4y + 1)
I guess this is easier
