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Answer :

Wegnerkolmp2741ogo

Answer:

(x-3)^2 = 5

x = 3 ±sqrt(5)

Step-by-step explanation:

x ^2 −4x+4=2x

Subtract 2x from each side

x ^2 −4x-2x+4=2x-2x

x^2 -6x +4 = 0

Subtract 4 from each side

x^2 -6x+4-4 =0-4

x^2 -6x = -4

Take -6

Divide by 2

-6/2 = -3

Square it

(-3)^2 = 9

Add to each side

x^2 -6x+9 = -4+9

(x-3)^2 = 5

Take the square root

sqrt((x-3)^2) = ±sqrt(5)

x-3 =  ±sqrt(5)

Add 3 to each side

x = 3 ±sqrt(5)

TestimonyofGodgo

Answer:

lusing completing square metjod

x

Step-by-step explanation:

x^2_6x+(_3)^2=_4+9

(x_3)^2=5

x_3=

[tex] \sqrt{5} [/tex]

[tex]x = 3 + or - \sqrt{5} [/tex]

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