Answer :
If the perimeter of the garden is (14x - 32) ft and has a side length of (x + 2) ft:
- the perimeter = 24 ft
- the area = 36 sq. ft
- if the perimeter of the garden is doubled, the perimeter of the new garden = 48 ft
- if the area of the garden is doubled, the area of the new garden = 72 sq. ft
Recall:
- A square has equal side lengths
- Perimeter of a square = 4(side length)
- Area of a square = [tex](side $ length)^2[/tex]
Given:
Perimeter of square (P) = [tex](14x - 32) $ ft[/tex]
Side length (s) = [tex](x + 2) $ ft[/tex]
First, let's find the value of x by creating an equation using the perimeter formula:
- Perimeter of a square = 4(side length)
- Plug in the values
[tex](14x - 32) = 4(x + 2)[/tex]
- Solve for x
[tex]14x - 32 = 4x + 8\\\\14x - 4x = 32 + 8\\\\10x = 40\\\\x = 4[/tex]
Find how much fencing would be needed (Perimeter of the fence):
- Perimeter of the fence = [tex](14x - 32) $ ft[/tex]
- Plug in the value of x
Perimeter of the fence = [tex]14(4) - 32 = 24 $ ft[/tex]
Find the area of the garden:
- Area of the garden = [tex](side $ length)^2[/tex]
Area = [tex](x + 2)^2[/tex]
- Plug in the value of x
Area = [tex](4 + 2)^2 = 6^2 = 36 $ ft^2[/tex]
Find the perimeter if the garden size is doubled:
- Perimeter of the new garden = 2 x 24 = 48 ft
Find the area if the garden size is doubled:
- Perimeter of the new garden = 2 x 36 = 72 sq. ft
In summary, if the perimeter of the garden is (14x - 32) ft and has a side length of (x + 2) ft:
- the perimeter = 24 ft
- the area = 36 sq. ft
- if the perimeter of the garden is doubled, the perimeter of the new garden = 48 ft
- if the area of the garden is doubled, the area of the new garden = 72 sq. ft
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