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Answer :

[tex]\huge \bf༆ Answer ༄[/tex]

Let's solve ~

[tex]\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} } [/tex]

[tex]\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times 3{k}^{4} } [/tex]

[tex]\qquad \looparrowright \sf - 2 \times 2 {}^{3} \times {k}^{2} \times \sqrt{3} [/tex]

[tex]\qquad \looparrowright \sf - 16 {k}^{2} \sqrt{3} [/tex]

Hence, the correct choice is D

square root of 192 can be simplified to
8 sqrt(3)
square root of k^4 can be simplified to
k^2
multiply that and the -2 to get:
-16k^2 sqrt(3)

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