Answer:
B'(-9, -1)
Step-by-step explanation:
Rule for rotating 180° : (x, y) →(-x, -y)
A square with corners at A(2, 1), B(9, 1), C(9, 8), and D(2, 8) if rotated 180 degrees counterclockwise about the origin will produce image A'( -2,-1), B'(-9, -1), C'(-9,-8), D'(-2, -8).
At which point is image corner B' located?
B'(-9, -1)
