The answer is "[tex]-\frac{8}{9} \\\\[/tex]".
Given:
[tex]\to \frac{2}{5}n+3-\frac{7}{10}n=\frac{3}{5}-3n[/tex]
To find:
n=?
Solution:
[tex]\to \frac{2}{5}n+3-\frac{7}{10}n=\frac{3}{5}-3n\\\\\to \frac{2}{5}n-\frac{7}{10}n+3n=\frac{3}{5} -3\\\\\to n(\frac{4-7+30}{10})=\frac{3-15}{5} \\\\\to n(\frac{-3+30}{10})=\frac{3-15}{5} \\\\\to n(\frac{27}{10})=\frac{-12}{5} \\\\\to n=\frac{-12}{5} \times \frac{10}{27} \\\\\to n=-4 \times \frac{2}{9} \\\\\to n=-\frac{8}{9} \\\\[/tex]
Therefore, the final answer of n is "[tex]-\frac{8}{9} \\\\[/tex]".
Find out more information about solving here:
brainly.com/question/322601
