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Answer :

Answer:

1mole of AgNO3 contains 6.023×10²³molecules and weigh 108g+14g+16g×3=170g

6.023×10²³--------------170g

7.4×10²³--------------------x

cross multiply

x=(170×7.4×10²³)/(6.023×10²³)

x=208.86grams is the answer

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