Answer :
Answer:
1mole of AgNO3 contains 6.023×10²³molecules and weigh 108g+14g+16g×3=170g
6.023×10²³--------------170g
7.4×10²³--------------------x
cross multiply
x=(170×7.4×10²³)/(6.023×10²³)
x=208.86grams is the answer
please mark brainliest.
Answer:
1mole of AgNO3 contains 6.023×10²³molecules and weigh 108g+14g+16g×3=170g
6.023×10²³--------------170g
7.4×10²³--------------------x
cross multiply
x=(170×7.4×10²³)/(6.023×10²³)
x=208.86grams is the answer
please mark brainliest.