The pH of a solution that contains 0.0011 moles of KOH in 393 mL of solution is 2.56. Details about pH can be found below.
The pH of a solution can be calculated using the following expression:
pH = - log [H3O+]
However, the hydrogen concentration of the KOH solution can be calculated as follows:
concentration = 0.0011 mol ÷ 0.393 L
concentration = 2.798 × 10-³M
The pH of KOH = - log [2.798 × 10-³M]
pH = 2.56
Therefore, the pH of a solution that contains 0.0011 moles of KOH in 393 mL of solution is 2.56.
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