Answer :
Answer:
78
Step-by-step explanation:
plug in -3 as x
6(2(-3)^2-5)
6(2(9)-5)
6(18-5)
6(13)
78
Answer: 78
Step-by-Step Solution:
=> 6(2x² - 5) ; when x = -3
Substitute the value of ‘x’ :-
= 6(2x² - 5)
= 6(2(-3)² - 5)
= 6(2(9) - 5)
= 6(18 - 5)
= 6(13)
= 6 * 13
=> 78
Step-by-Step Solution:
=> 6(2x² - 5) ; when x = -3
Substitute the value of ‘x’ :-
= 6(2x² - 5)
= 6(2(-3)² - 5)
= 6(2(9) - 5)
= 6(18 - 5)
= 6(13)
= 6 * 13
=> 78