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A 22 foot ladder leans against a building. If the angle the ladder makes with the ground is 52 degrees, what is the distance between the building and the base of the ladder? Round to the nearest tenth.(Hint: Draw a picture) (6.8c)(1 point)

Answer :

Let's use cosine identity:

[tex]\begin{gathered} \cos (\theta)=\frac{adjacent}{hy_{}po_{}te_{}nu_{}se} \\ \cos (52)=\frac{dis\tan ce}{22} \\ dis\tan ce=22\cdot\cos (52)=13.54455246 \\ dis\tan ce\approx13.5ft \end{gathered}[/tex]

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