👤
Answered

Many metabolites are maintained at steady-state concentrations that are far from equilibrium. A comparison of K' and Q, the mass-action ratio, can determine whether a metabolic reaction is far from equilibrium.
The equation for this equilibrium is,
fructose 6-phosphate + ATP ⇄ fructose 1,6-bisphosphate + ADP
Calculate K' for this reaction at T=25.0°C
Δ G'=-14.2 kJ/mol
K'=
Calculate the mass-action ratio, Q, from the approximate physiological concentrations for rat heart tissue shown in the table.
Q=

Many Metabolites Are Maintained At Steadystate Concentrations That Are Far From Equilibrium A Comparison Of K And Q The Massaction Ratio Can Determine Whether A class=

Answer :

Go Teaching: Other Questions