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Find the value of x^3+3x^2y+3xy^2+y^3 when x=3 & y=4

Answer :

ChoiSungHyungo ChoiSungHyungo

Explanation:

Notice that x³ + 3x²y + 3xy²+ y³ is of the form

(x + y)³.

When x = 3 and y = 4,

(x + y)³ = [(3) + (4)]³ = 7³ = 343.

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