Answer:
1/2 * (5+3) * 6 = 24 cm^2
Step-by-step explanation:
Perimeter is 20
and it's a rectangle so 2x + 12= 20
x is 4 so one of parallel side of trapezium is 9-4 or 5 then just apply formula for area of trapezium
The area of the trapezium is [tex]60cm^{2}[/tex]
'A trapezium is a quadrilateral, which is defined as a shape with four sides and one set of parallel sides.'
According to the given problem,
AB = FC = 6cm
Perimeter of ABCF = 20cm
CB = FA
⇒ 20 = 6 + 6 + CB + CB
⇒ 8 = 2CB
⇒ CB = 4
Base 1 = CF = 6cm
Base 2 = DEDE = DB + BA + AEDB = AEDE = 9 + 6 + 9 = 24
Area = [tex]\frac{1}{2} * ( a + b ) * h[/tex]
h = 4a = Base 1 = 6b = DE = 24
Area of trapezium CDEF=[tex]\frac{1}{2}* (6+24)*4[/tex]
= [tex](2*30) cm^{2}[/tex] = [tex]60 cm^{2}[/tex]
Hence, we can conclude that the area of the trapezium is 60cm ².
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