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Answered

A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles.
If we choose a marble, then another marble without putting the first one back in the blag, what is the
probability that the first marble will be green and the second will be red?

Answer :

Answer:

number of green Ă· total number of marbles

times by

number of red Ă· total number of marbles left

so

(3/9) Ă— (2/8) = (1/12)

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