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A patient requires an IV of D5W, a 5% solution of dextrose (sugar) in water. To the nearest milliliter, how much D20W, a 20% solution of dextrose in water, must be added to 100 milliliters of distilled water to produce a D5W solution? Please show all work.

Answer :

Okpalawalter8go

Answer:

  [tex]A=300ml[/tex]

Step-by-step explanation:

From the question we are told that

5% solution of dextrose sugar in water

20% solution of dextrose in

100 milliliters of distilled water water

Generally in mathematically solving we call A the amount of D20W added

Since 20% of dextrose is needed

       [tex]20 \%*100=20milliter[/tex]

Total quantity after addition (100+x)

for DW5% total solution is

          [tex]5\% (100+A)= \frac{5}{100}(100+A)[/tex]

          [tex]5\% (100+A) =5+0.05A[/tex]

Mathematically

           [tex]5+0.05A =20[/tex]

           [tex]5+0.05A =20-5[/tex]

           [tex]A=\frac{15}{0.05}[/tex]

           [tex]A=300ml[/tex]

Therefore the required quantity [tex]A=300ml[/tex]

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