The required value for the mass of object is 0.06 kg.
Given data:
The speed of object is, v = 3.0 m/s.
The distance travelled by object is, s = 0.090 m.
From the given graph in the question, we obtain the following details as,
The net force applied on the object is, [tex]F_{net}=3\;\rm N[/tex].
The initial velocity is, u = 0 m/s.
Now using the third kinematic equation of motion to obtain the acceleration of object as,
v² = u² + 2as
3² = 0² + (2 × a × 0.09)
9 = 0 + 0.18a
9 = 0.18a
Solving as,
a = 9 / 0.18
a = 50 m/s²
Now, as per the Newton's second law of motion, we have the expression for the applied force as,
[tex]F_{net}= ma[/tex]
Here, m is the mass of object.
Solving as,
[tex]3= m \times 50\\\\m = 0.06 \;\rm kg[/tex]
Thus, we can conclude that the required value for the mass of object is 0.06 kg.
Learn more about the Newton's second law here:
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