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Answer :

Answer:  1/36

Explanation:

The probability of rolling a "2" is 1/6

The probability of rolling a "4" is also 1/6

Multiplying those fractions leads to (1/6)*(1/6) = 1/36. We can multiply the probabilities because the events are independent. Each dice roll does not affect any others.

MrRoyalgo

The probability of rolling a 2 the first time and a 4 the second time is 1/36

There are 6 faces on a die.

Of these 6 faces, one of them is 2 and one of them is 4

So, the probabilities of rolling a 2 and a 4 are:

P(2) = 1/6

P(4) = 1/6

The probability of rolling a 2 the first time and a 4 the second time is calculated as follows:

[tex]\mathbf{Pr = P(2) \times P(4)}[/tex]

This gives

[tex]\mathbf{Pr = \frac 16 \times \frac 16}[/tex]

Multiply

[tex]\mathbf{Pr = \frac 1{36}}[/tex]

Hence, the probability of rolling a 2 the first time and a 4 the second time is 1/36

Read more about probabilities at:

https://brainly.com/question/11234923

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