Answer:
[tex]\boxed{\boxed{\pink{\bf \leadsto The \ 22nd \ term \ is \ 71. }}}[/tex]
Step-by-step explanation:
Given that the nth term of the Arthemetic Sequence is given by :-
[tex]\implies f(n) = 8 + 3(n-1) [/tex]
And we need to find the 22nd term .
So in place of n substitute 22 .
[tex]\bf\implies f(n) = 8 + 3(n-1) \\\\\bf\implies f_{22} = 8 + 3(22-1) \\\\\bf\implies f_{22} = 8 + 3\times 21 \\\\\bf\implies f_{22} = 8 + 63 \\\\\bf\boxed{\bf\implies f_{22} = 71 }[/tex]
Hence the 22nd term is 71 .
