Answer:
0.200 mol.
Explanation:
Hello!
In this case, since this case is considered an ideal one (no intermolecular interactions), we can use the following equation:
[tex]PV=nRT[/tex]
Thus, since we know the pressure, temperature and volume, we are able to compute the moles shown below:
[tex]n=\frac{PV}{RT} =\frac{191kPa*\frac{1000Pa}{1kPa} *6.5L*\frac{1m^3}{1000L} }{8.314\frac{Pa*m^3}{mol*K}*750.0K}\\\\n=0.200mol[/tex]
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