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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 5.9 parts/million (ppm). A researcher believes that the current ozone level is not at a normal level. The mean of 24 samples is 5.6 ppm with a standard deviation of 1.0. Assume the population is normally distributed. A level of significance of 0.02 will be used. Find the value of the test statistic. Round your answer to three decimal places.

Answer :

Answer:

t = -0.061

Step-by-step explanation:

We are given;

Population mean; μ = 5.9

Sample mean; x¯ = 5.6

Sample size; n = 24

standard deviation; σ = 1

Significance level = 0.02

Formula for the test statistic since sample size is less than 30 is;

t = (x¯ - μ)/(σ/√n)

t = (5.6 - 5.9)/(1/√24)

t = -0.3/(1/√24)

t = -0.061

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