Answer :
Answer:
[tex]n + d = 368[/tex]
[tex]0.05n + 0.10d = 28.40[/tex]
Step-by-step explanation:
Given
[tex]Total = 368[/tex]
[tex]Value = \$28.40[/tex]
Required
Determine the linear equations to represent the scenario
Represent nickel with n and dimes with d
So, the total is:
[tex]n + d = 368[/tex]
[tex]1\ nickel = \$0.05[/tex]
[tex]1\ dime = \$0.10[/tex]
So, the value is:
[tex]0.05n + 0.10d = 28.40[/tex]
Hence, the linear equations are:
[tex]n + d = 368[/tex]
[tex]0.05n + 0.10d = 28.40[/tex]
The system of linear equations and solution can be used to represent the number of nickels and dimes Matthew has in his collection is n + d = 368 0.05n + 0.1d=28.4 168 nickels and 200 dimes.
Given that,
- Matthew has a jar of 368 nickels and dimes he has been collecting.
- The total value of the coins is $28.40.
- Here we take n be nickles and d be dimes.
- Also, 1 nickel be = $0.05 and 1 dime be $0.10.
Based on the above information, the calculation is as follows:
n + d = 368
So,
d = 368 - n
And,
0.05n + 0.10d = 28.40
0.05n + 0.10(368 - n) = 28.40
0.05n + 36.8 - 0.10n = 28.40
0.05n = 8.4
n = 168
So, d = 368 - 168
= 200
Therefore we can conclude that the correct option is A.
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