Answer :
Answer:
22.48m
Explanation:
Given that the pool deck platform is 4 m above the ground.
The initial velocity of mortar in the upward direction, u=21 m/s
At the maximum height, the velocity of the mortar will become zero.
So, the final velocity, v=0
Acceleration due to gravity, g = 9.81 m/[tex]s^2[/tex] in the downward direction.
By using the equation of motion [tex]v^2=u^2+2as\\[/tex]
On putting all the values, we have
[tex]0^2=21^2+2(-9.81)s\\\\s=21^2/(2\times 9.81)[/tex]
s= 22.48 m
Hence, the mortar will reach a maximum height of 22.48m.