The given question is an incomplete question, the complete question is given below.
Use this equation to answer the questions that follow.
[tex]3O_2(g)+N_2(g)\rightarrow 2NO_3(g)[/tex]
5 moles of oxygen gas are present. How many moles of [tex]NO_3[/tex] will be produced with this amount of oxygen gas?
Answer : The moles of [tex]NO_3[/tex] produced will be 3.33 moles.
Explanation : Given,
Moles of oxygen gas = 5 moles
Now we have to calculate the moles of [tex]NO_3[/tex].
The given balanced chemical equation is:
[tex]3O_2(g)+N_2(g)\rightarrow 2NO_3(g)[/tex]
From the balanced chemical equation we conclude that,
As, 3 moles of [tex]O_2[/tex] gas react to produces 2 moles of [tex]NO_3[/tex] gas
So, 5 moles of [tex]O_2[/tex] gas react to produces [tex]\frac{2}{3}\times 5=3.33[/tex] moles of [tex]NO_3[/tex] gas
Therefore, the moles of [tex]NO_3[/tex] produced will be 3.33 moles.
