Answer :
Answer:
here you goes hope it helps you
Step-by-step explanation:
1
Common factor
β
3
2
+
7
+
2
0
-3y^{2}+7y+20
β3y2+7y+20
β
1
(
3
2
β
7
β
2
0
)
-1(3y^{2}-7y-20)
β1(3y2β7yβ20)
2
Use the sum-product pattern
β
1
(
3
2
β
7
β
2
0
)
-1(3y^{2}{\color{#c92786}{-7y}}-20)
β1(3y2β7yβ20)
β
1
(
3
2
+
5
β
1
2
β
2
0
)
-1(3y^{2}+{\color{#c92786}{5y}}{\color{#c92786}{-12y}}-20)
β1(3y2+5yβ12yβ20)
3
Common factor from the two pairs
β
1
(
3
2
+
5
β
1
2
β
2
0
)
-1(3y^{2}+5y-12y-20)
β1(3y2+5yβ12yβ20)
β
1
(
(
3
+
5
)
β
4
(
3
+
5
)
)
-1(y(3y+5)-4(3y+5))
β1(y(3y+5)β4(3y+5))
4
Rewrite in factored form
Solution
β
1
(
β
4
)
(
3
+
5
)