Explanation:
I won't answer each of these, but will give you an explaination of how to solve for each.
You'll need to use Ohm's Law and Kirchhoff's Voltage Law.
Remember Ohm's Law as [tex]V = IR[/tex].
Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.
[tex]E_T = E_1 + E_2 + E_3[/tex]
A couple of other helpful notes:
These three resistors are in series which means that the current flowing through them is equal.
So it is easy to see that... [tex]V = IR \rightarrow E_1 = 4*2 = 8 V[/tex]
Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).
