Moles of hydronium (H₃O⁺) : 2.5 x 10⁻⁴
Given
pH = 4.3
V sample = 5 L
Required
moles of H₃O⁺(hydronium)
Solution
pH = - log [H₃O⁺]
4.3 = - log [H₃O⁺]
[tex]\tt [H_3O^+]=10^{-4.3}~M=10^{-4.3}mol/L[/tex]
Moles of hydronium for 5 L sample :
[tex]\tt 5~L\times 10^{-4.3}mol/L=5.10^{-4.3}moles=2.5\times 10^{-4}~moles[/tex]
