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When you drop a 0.38 kg apple, Earth exerts
a force on it that accelerates it at 9.8 m/s’ to-
Ward the earth's surface. According to New-
ton's third law, the apple must
exert an equal but opposite force on earth. If the mass of the Earth is 5.98 x 10^24 kg, what is the magnitude of the Earth’s acceleration towards the apple? Answer in units or m/s^2

Answer :

NusrathCgo

Answer:

6.2 ×10^-25

Explanation:

Ma = mg

a = (m/M)g

[tex]a = \frac{0.38}{5.98 \times {10}^{24} } \times 9.8 = 6.2 \times {10}^{ - 25} [/tex]

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