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A particular spring has a spring constant of 25 N/m.
Calculate the energy stored when the spring is extended by 15 mm.
Give your answer in standard form, to 3 significant figures.

Answer :

NusrathCgo

Answer:

2.8×10^-3

[tex]e.p.e = \frac{1}{2} k {x}^{2} \\ = \frac{1}{2} \times 25 \times (0.015m)^{2} \\ = 0.0028125[/tex]

0.0028125N

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