Answer:
C. [tex]p_{A} = -p_{B}[/tex] and [tex]K_{A} = K_{B}[/tex].
Explanation:
The two hockey pucks travels in opposite sides with velocities of same magnitude, by definitions of linear momentum and translational kinetic energy:
Linear momentum
Hockey puck A
[tex]p_{A} = m\cdot v[/tex] (1)
Hockey puck B
[tex]p_{B} = -m\cdot v[/tex] (2)
[tex]p_{A} = -p_{B}[/tex]
Translational kinetic energy
Hockey puck A
[tex]K_{A} = \frac{1}{2}\cdot m\cdot (v)^{2}[/tex]
[tex]K_{A} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (3)
Hockey puck B
[tex]K_{B} = \frac{1}{2}\cdot m\cdot (-v)^{2}[/tex]
[tex]K_{B} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (4)
[tex]K_{A} = K_{B}[/tex]
Hence, the correct answer is C.
