Answer:
C. (-2, 0)
Step-by-step explanation:
[tex]y = 3x + 6[/tex]
[tex]y = 2x + 4[/tex]
Since both equations equal y, set them equal to each other.
[tex]3x + 6 = 2x + 4[/tex]
[tex]x + 6 = 4[/tex]
[tex]x = -2[/tex]
Substitute -2 for x in the first equation.
[tex]y = 3x + 6[/tex]
[tex]y = 3(-2) + 6[/tex]
[tex]y = -6 + 6[/tex]
[tex]y = 0[/tex]
[tex](-2, 0)[/tex]
Now, substitute the x- and y-values into the second equation.
[tex]y = 2x + 4[/tex]
[tex]0 = 2(-2) + 4[/tex]
[tex]0 = -4 + 4[/tex]
[tex]0 = 0[/tex]
It works! The soluton to the system of equations is (-2, 0).
