Answer:
Step-by-step explanation:
so these two lines cross at some point.. and they want to know the y point at which they cross... sooo..
solve them as a system to find the points that are common to both
Eq. 1) 5x -2y = 16
Eq. 2) -4x+6y=-15
i'll use the elimination method as these equations "lend" themselves to that way.. they are easy to solve that way .. in other words..
multiply Eq. 1 by 3 the add Eq. 2 .. to it... add the terms as columns....
15x-6y = 48
+ ( -4x+6y=-15)
= 11x+ 0y =33
x=3
nice, now plug 3 in for x in one of the Eq. try Eq. 1
5(3)-2y=16
15-2y=16
-2y =1
y = [tex]-\frac{1}{2}[/tex]
since we're looking for the y coordinate... that's your answer [tex]-\frac{1}{2}[/tex]
