Answer :
Answer:
from second equation of motion
[tex]S = ut + \frac{1}{2} a {t}^{2} \\ S = (50 \times 20) + (\frac{1}{2} \times 3 \times {20}^{2} ) \\ S = 1000 + 600 \\ S = 1600 \: m[/tex]
Answer:
from second equation of motion
[tex]S = ut + \frac{1}{2} a {t}^{2} \\ S = (50 \times 20) + (\frac{1}{2} \times 3 \times {20}^{2} ) \\ S = 1000 + 600 \\ S = 1600 \: m[/tex]