Answer:
Step-by-step explanation:
1) AC⊥BD and BD bisects AC 1) given
2) AD≅DC 2) linear bisector thm.
3) ∠ADB and ∠CDB are right angles 3) perpendicular bisector thm.
4) ∠ADB ≅ ∠CDB 4) all right ∡'s are congruent
5) BD ≅ BD 5) reflexive POV
6) ΔABD ≅ ΔCBD 6) SAS
Hope this helps!
btw, I was not able to put the lines on top of some of the letters, so my apologies.
