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During a laboratory experiment, you discover that an enzyme-catalyzed reaction has a â–³G of -20 kcal/mol. If you double the amount of enzyme in the reaction, what will be the â–³G for the new reaction?


A. +20 kcal/mol

B. -40 kcal/mol

C. -20 kcal/mol

D. -10 kcal/mol

Answer :

Answer:

Option-C

Explanation:

Delta G (â–³G) refers to the overall energy released during a chemical reaction when equilibrium is reached i.e the rate of conversion of product into the substrate is equal to the rate of conversion of substrate into product. Thus, â–³G accounts for the equilibrium of the reaction.

In the given question, it has been mentioned that â–³G of a reaction is -20 kcal/mol then how will it change if the amount of enzyme is doubled.  

The â–³G is not affected by the enzyme concentration as the presence of enzyme affects the G (Gibbs free energy) and activation energy.

Therefore, â–³G will remain the same even if the amount of enzyme is doubled i.e -20 kcal/mol will be the correct value.

Thus, Option-C is the correct answer.

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