What are the answers to the last two questions?

Answer:
[tex](-1)(x+3)(x-2)[/tex]
Step-by-step explanation:
Factoring
We are given a trinomial:
[tex]-x^2-x+6[/tex]
The following steps are done to factor the trinomial.
1. Confirm there are no common factors: No common factors (given)
2. Factor out -1:
Multiply all the terms by -1 and take -1 out:
[tex]\boxed{(-1)(x^2+x-6)}[/tex]
3. Factor
[tex]x^2+x-6 = (x+p)(x+q)[/tex]
We have to find two numbers p and q whose product is -6 and the sum is 1. Those numbers are 3 and -2 (in any order):
Factoring:
[tex]x^2+x-6 = (x+3)(x-2)[/tex]
The final factoring is:
[tex]\boxed{(-1)(x+3)(x-2)}[/tex]