What are the answers to the last two questions?

Answer:
1. (-1)(x^2+x-6)
2. (-1)(x+3)(x-2)
Step-by-step explanation:
Factoring
It's given the trinomial
[tex]-x^2-x+6[/tex]
1. There is no common factor (given).
2. Factor out -1:
Each term is divided by -1:
[tex]\mathbf{(-1)(x^2+x-6)}[/tex]
3. Now we factor the remaining trinomial. We find two numbers whose sum is 1 and the product is -6. These are 3 and -2, thus the trinomial is:
(-1)(x+3)(x-2)