Answer:
[tex]D= -0.42km[/tex]
Explanation:
From the question we are told that
Drifting right with speed 5.0m/s
The motor runs for 6.0 seconds
Leftward acceleration of magnitude 4.0 m/s squared
Generally the equation [tex]V=ut+1/2at^2[/tex] can be used here
[tex]V=ut+1/2at^2[/tex]
Mathematically solving with the newton equation above we have that
[tex]D=5*6 + \frac{1}{2} (-4)*6^2[/tex]
[tex]D=30-72[/tex]
[tex]D=-42m[/tex] [tex]or -0.42km[/tex]
Therefore having this the Displacement is [tex]D= -0.42km[/tex] leftward
