Answer:
The area of circle 1 is 9 times greater than area of circle 2.
Step-by-step explanation:
Given that:
Radius of circle 1 = 12
Area of circle 1 = πr²
Area of circle 1 = [tex]3.14*(12)^2 = 3.14*144[/tex]
Area of circle 1 = 452.16
Radius of circle 2 = 4
Area of circle 2 = [tex]3.14*(4)^2 = 3.14*16[/tex]
Area of circle 2 = 50.24
Let,
x be the number of times circle 1 is bigger than circle 2.
Area circle 1 = x * Area circle 2
[tex]\frac{452.16}{50.24}=\frac{50.24x}{50.24}\\\\x=9[/tex]
Hence,
The area of circle 1 is 9 times greater than area of circle 2.
