Work out angle BXC.
Give a reason for each angle you work out.

Answer:
∠ BXC = 70°
Step-by-step explanation:
∠ XBC and ∠ AXY are corresponding angles and are congruent, then
∠ XBC = 55°
Since XB = XC , then Δ XBC is isosceles and the 2 base angles are congruent.
∠ BXC = 180° - (55 + 55)° ← angle sum of triangle
∠ BXC = 180° - 110° = 70°
The measure of angle BXC is 70°
"It is a line that passes through two lines in the same plane at two different points."
"These are the lines in the same plane that are at equal distance from each other and never meet."
"It is a triangle having any two sides equal in length."
For given example,
We can observe that XY and BD are parallel lines and AB is the transversal.
Here,
∠AXY = ∠XBC ..............(Corresponding angles)
⇒ ∠XBC = 55°
In figure, for ΔXBC the sides XB and XC are equal.
So, ΔXBC is an isosceles triangle.
We know, for isosceles triangle, angles opposite to equal sides are equal in measure.
⇒ ∠XBC = ∠XCB
⇒ ∠XCB = 55°
We know, the sum of all angles of the triangle is 180°.
⇒ ∠XBC + ∠XCB + ∠BXC = 180°
⇒ 55° + 55° + ∠BXC = 180°
⇒ 110° + ∠BXC = 180°
⇒ ∠BXC = 70°
Therefore, the measure of angle BXC is 70°
Learn more about the angles formed by parallel line and transversal here:
https://brainly.com/question/15464186
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