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Physics

Answered

5. How much power is dissipated when 0.2 ampere of current flows through a 100-ohm resistor ?

Answer :

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Answer:

P=I*I*R

Where P is power

I is current

R is Resistance

P=2*2*100

P=400W

Explanation:

Power is the rate of doing work.

From the Ohm’s law V=IR

Power=I*I*R

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