Answer:
x = 2[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + (2[tex]\sqrt{2}[/tex] )² = 4²
x² + 8 = 16 ( subtract 8 from both sides )
x² = 8 ( take the square root of both sides )
x = [tex]\sqrt{8}[/tex] = 2[tex]\sqrt{2}[/tex]
