Answer :
Given:
Seeds planted = [tex]1\dfrac{2}{3}[/tex] rows
Crows ate = [tex]1\dfrac{1}{5}[/tex] rows
To find:
The remaining rows of seeds.
Solution:
According to the question,
Remaining rows of seeds = Seeds planted - Crows ate
[tex]=1\dfrac{2}{3}-1\dfrac{1}{5}[/tex]
[tex]=\dfrac{1(3)+2}{3}-\dfrac{1(5)+1}{5}[/tex]
[tex]=\dfrac{3+2}{3}-\dfrac{5+1}{5}[/tex]
[tex]=\dfrac{5}{3}-\dfrac{6}{5}[/tex]
Taking LCM, we get
[tex]=\dfrac{5(5)-3(6)}{15}[/tex]
[tex]=\dfrac{25-18}{15}[/tex]
[tex]=\dfrac{7}{15}[/tex]
Therefore, [tex]\dfrac{7}{15}[/tex] rows of seeds are left.