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-) A sample of oxygen had an initial volume of 25.0L and was at a standard pressure of
30atm, what would the new volume be if the pressure was increased to 55.00 atm?

Answer :

Answer:

13.64 L

Explanation:

The new volume can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

From the question we have

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

From the question we have

[tex]V_2 = \frac{25 \times 30}{55} = \frac{750}{55} \\ = 13.636363...[/tex]

We have the final answer as

13.64 L

Hope this helps you

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